6x^2-9x-25=-(x+0.2)

Solution for 6x^2-9x-25=-(x+0.2) equation:

6x^2-9x-25=-(x+0.2)

We move all terms to the left:

6x^2-9x-25-(-(x+0.2))=0


We calculate terms in parentheses: -(-(x+0.2)), so:

-(x+0.2)

We get rid of parentheses

-x-0.2

We add all the numbers together, and all the variables

-1x-0.2

Back to the equation:

-(-1x-0.2)


We get rid of parentheses

6x^2-9x+1x+0.2-25=0

We add all the numbers together, and all the variables

6x^2-8x-24.8=0

a = 6; b = -8; c = -24.8;
Δ = b2-4ac
Δ = -82-4·6·(-24.8)
Δ = 659.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{659.2}}{2*6}=\frac{8-\sqrt{659.2}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{659.2}}{2*6}=\frac{8+\sqrt{659.2}}{12}
$